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RDAS Temperature Correction

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Larry Curcio - 29 Mar 2007 11:51 GMT
So I have been fooling with RDAS data from many
different sources. Over and over the question of
temperature correction arises. Plane altimeters are
calibrated WRT sea level, which is assumed to be
15 degrees C or 59 degrees F. I had been figuring that
most rocket altimeters were calibrated at ground level
(the AltAcc is an exception, BTW), and that ground
level is presumed to be 15 degrees C.

I was able to produce RDAS nominal altitudes by taking
their raw reading and adding 128. The result seems to be
the uncalibrated pressure reading. The average of the values
corresponding to negative times seems to serve as the base
pressure. One then takes every subsequent reading and divides
by this. The result is a pressure ratio that is substituted into
standard altimeter equations. These equations involve
temperature.

The temperature that corresponds to the best fit with the RDAS
nominal altitudes is 0 degrees C or 32 degrees F. If this is correct
then the nominal barometric altitudes put out by RDAS units
should be multiplied by the following factor

FACTOR = (273.15 + Tc)/273.25

where Tc is the centigrade temperature of the launch site.

In the samples I have tried, which now amount to 4, the result is
a very much better correspondence between inertial and
barometric altitudes.

Regards,
Larry (All opinion. No warranties express or implied) C
jsdemar - 29 Mar 2007 16:21 GMT
Did you ask the AED people about this "feature"?

> So I have been fooling with RDAS data from many
> different sources. Over and over the question of
[quoted text clipped - 29 lines]
> Regards,
> Larry (All opinion. No warranties express or implied) C
Larry Curcio - 31 Mar 2007 14:34 GMT
Hi, John.

Actually, temperature correction is not peculiar
to RDAS. Most altimeters require it. It has always
been an issue with the FAA, and is more so now
that some planes use GPS and others use altimeters.

(I didn't read your email carefully, I've been at work
forever. You gave me a reference. Was this it?)

1)http://www.faa.gov/regulations_policies/rulemaking/historical_documents/1999/med
ia/ac91-xx.pdf


I did not think it news to anyone that temperature

correction is important. I was surprised that, in the

samples I tested, the base temperature appeared to

be 0 degrees C, and not 15 degrees. The most

controversial part of the whole thing is my value

of 128 for the displacement. It seems to work

better than other values I tried, and it is a round

number in binary.

Let me summarize a couple of other points:

1)Now that I think about it, I cannot characterize

all RDAS altimeters in exactly this way. Three

of my samples are from 2003. These were taken

at ~34 degrees C. I have another data set, the

vintage of which I cannot vouch for that is taken

at -15 degrees C. That dataset is not in raw form,

but is in intrpreted form. That is, the altitudes are

already computed. The R^2 statistic between

untransformed inertial altitude and barometric

altitude goes up from .94 to .9996 with the

conversion. The same sort of thing happened

with the other data sets, which were taken at

very different temperatures.

Perhaps later versions of the instrument do things

differently.

2) Check out the formula I suppled in my reply

to Dave Schultz. Note that since pressure is a

ratio, it may be represented in only relative

units. Most units, including RDAS, allow one

to download raw data. One normally adds/subtracts

a displacement from that (in my samples, it

seemed to be 128) and takes a ratio of each

individual reading to a ground reading. (I averaged the

negative time values.) Substitute that into the formula

using your actual base altitude temperature and you get

a calibrated altitude value. You don't need the value that

RDAS gives you, which is likely a (very very good)

polynomial approximation

Do a linear regression on the nominal values and you

can estimate the base temperature used by RDAS. Indeed,

the intercept is an estimate of the reference altitude.

(Problem is the regressor variable, whichever you choose,

has noise, so there is some bias. The intercept tends to be

bigger than it should be.)

Some units claim to be temperature corrected. The data have

seen with RDAS are not consistent with temperature correction,

IMHO - or temperature correction means something other

than the issue detailed here.

See my next (short) post.

Regards,

-Larry
David Schultz - 30 Mar 2007 00:42 GMT
> So I have been fooling with RDAS data from many
> different sources. Over and over the question of
[quoted text clipped - 13 lines]
> standard altimeter equations. These equations involve
> temperature.

In the pressure/altitude conversion equations I have seen the
temperature decreases linearly with altitude. At least at some altitudes.

http://www.grc.nasa.gov/WWW/K-12/airplane/atmos.html

So I am not sure how temperature correction helps. Besides, if I recall
my density altitude stuff correctly the pressure stays the same but the
density decreases. I have yet to find any reasonably authoritative work
that describes how to use a base pressure and temperature other than
that in the standard atmosphere model to calculate altitude.

Using a ratio of apogee pressure to pre-launch pressure in these
equations is an error in my opinion. Instead the two pressures should be
converted to altitude and the difference between the two altitudes used.

While I do not know how the RDAS GUI software performs the conversion,
the rdtools package uses:

log(pressure / 1015.76) / -0.000123

(Note: In this particular case the properties of the logarithm make
using the pressure ratio identical to using the difference in altitudes.

http://www.rocket.flyer.co.uk/rdtools/

Note that this log equation diverges significantly from the standard
atmosphere table at:

http://www.pdas.com/e2.htm

While the equation on the NASA page does not.

(288.14 - 288.08 * pow(P/101.29, 1/5.256)) / 0.00649

> The temperature that corresponds to the best fit with the RDAS
> nominal altitudes is 0 degrees C or 32 degrees F. If this is correct
[quoted text clipped - 11 lines]
> Regards,
> Larry (All opinion. No warranties express or implied) C

Signature

David W. Schultz
http://home.earthlink.net/~david.schultz
------
David Shatzer - the new Douglas Feith?

Larry Curcio - 31 Mar 2007 14:11 GMT
Hi, Dave.

> In the pressure/altitude conversion equations I have seen the
> temperature decreases linearly with altitude. At least at some altitudes.
>
> http://www.grc.nasa.gov/WWW/K-12/airplane/atmos.html

Yup. I have actually measured this on a takeoff
and landing of a jet liner. Standard rate is 6.5 Kelvins
per kilometer. I measured 6.38 over Beijing and 5.78
over Newark. Turns out such lapse rate differences
make for trivial errors in the formula.

FWIW, in the lower stratosphere, the lapse rate is zero.
It eventually reverses higher up, as ozone absorbs light
energy.

> So I am not sure how temperature correction helps.
Altimeter formulas are based on two principles:
the first law of thermodynamics and hydrostatic
equilibrium.

Hydrostatic equilibrium says that at any altitude,
the the pressure on a given horizontal area of air
is balanced by the weight of the column of air
above it. That weight is affected by the temperature
of the air as the temperature lapses. It works out to

Const HC = 0.03418155
Const LapseRate = 0.0065

BaseTemp = BaseTempC + ZeroC

Ratio = PressRead / MeanGroundPressure

Altitude = (BaseTemp / LapseRate) * (1 - (Ratio ^ (LapseRate/HC))

Note that the whole thing is proportional to base temperature.

>Besides, if I recall my density altitude stuff correctly the pressure stays
>the same but the density decreases. I have yet to find any reasonably
[quoted text clipped - 5 lines]
> equations is an error in my opinion. Instead the two pressures should be
> converted to altitude and the difference between the two altitudes used.

Well, this stuff isn't exactly controversial. :-)

I'm a little behind (OK. Some would say I'm a big behind...)
on this thread as I have production issues at work and have
to go in today, Saturday. Will reply to John D. and fill in more there.
The issue is involved.

Good to hear from you.
-Larry Curcio

and summarize to
Larry Curcio - 31 Mar 2007 14:38 GMT
I have a long treatise on rockets, and within
it is a shorter long treatise on altimeter
formulas, where this stuff is derived. I can
excise this and email it to anyone who wants
it. It is in MSWord. Maybe I can turn it into
a PDF.

It covers this topic in excruciating detail.

It may be a couple of days. Busy busy.
 
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