Hi All,
I have recently finished making a small ride-in landrover for my
grandsons and have a question regarding the electric motor that drives
it. The initial 'road-test' proved excellent but was a little
dissapointing when attempting gentle uphill gradients which caused to
motor to stall so I just wanted to sound out some expert advise before
I decide on how to solve the problem.
I am using a 24volt dc Parvalux motor rated at 200w. I am currently
running the motor from a 12volt battery and the drive is geared down
to run the landrover at a comfortable walking pace.
My questions are as follows:
1. By applying half the rated voltage (12v instead of 24v) am I
reducing the power output to 100watts, or just reducing the motor
speed by half, or both?
2. Depending on the answer to Q1, if I increase the supply voltage to
24v will I need to adjust the gearing to maintain the current walking
pace speed (if the motor will be running twice as fast) and will I
have more power available to take reasonable uphill gradients?
I hope my questions make sense and that someone can help!
Regards, Martin.
Alan Marshall - 28 Apr 2007 13:02 GMT
I do not know the motor in question but usually on DC motors the speed and
power are directly proportional to the applied voltage. At 200 watts you
will have about 1/4 HP available which geared down may well be sufficient
for your needs. If you can run to it I would fit a 4QD controller that would
give you much better control over speed.
pentagrid@yahoo.com - 28 Apr 2007 14:08 GMT
>Hi All,
>
[quoted text clipped - 22 lines]
>
>Regards, Martin.
It depends on what type of DC motor - series wound, shunt
wound or permanent magnet field. For ALL types maximum power at
12V will be less than half the rated power.
A shunt wound machine will try to run at the same speed
but the efficiency will be dreadful because of the inadequate
field strength.
A series wound machine will be more tolerant of reduced
voltage. The speed will be very load dependent, but at the same
load it will run at a bit less than half the speed.
A permanent magnet machine will run a bit below half
speed but with much better speed regulation.
By doubling the supply voltage you will more than double
and possibly quadruple the output power. This should greatly
improve the hill climbing. The more the than double change in
straightline speed may be a problem and you would need the change
the gearbox ratio or add a power controller.
Jim
clutch@lycos.com - 28 Apr 2007 15:10 GMT
>1. By applying half the rated voltage (12v instead of 24v) am I
>reducing the power output to 100watts, or just reducing the motor
>speed by half, or both?
Power is squared. You reduced the power to 50 watts if I have my P=IE
E=IR stuff interpreted correctly.
Wes
Wayne Weedon - 28 Apr 2007 19:10 GMT
> I hope my questions make sense and that someone can help!
My suggestion is to find yourself a PWM controller for your motor and
run at 24v. There are probably 100's to chose from, some of the
robotics sites may be good for information.
Wayne....
steambuff - 28 Apr 2007 22:32 GMT
> > I hope my questions make sense and that someone can help!
>
[quoted text clipped - 3 lines]
>
> Wayne....
Thanks chaps for all your replies! It would appear to me that to get
the rated 200w output from my motor I need to be running on 24v,
furthermore I need to change the gear ratio (or get a pair of running
shoes!) as it would seem that motor speed will increase also. I don't
particularly want to go down the road (excuse the pun) of electronic
speed control as it will only cost about £15 to change the gears. Zero
to walking pace in 0.5 secs is adequate acceleration for a budding 6
yr old Schumaker and plenty enough for my ageing legs too! <G>
Regards, Martin.
Mark Rand - 28 Apr 2007 23:38 GMT
>> > I hope my questions make sense and that someone can help!
>>
[quoted text clipped - 14 lines]
>
>Regards, Martin.
Speed will double if it's a permanent magnet motor, It should stay about the
same if it's a shunt wound motor.
Mark Rand
RTFM
pentagrid@yahoo.com - 29 Apr 2007 09:22 GMT
>> > I hope my questions make sense and that someone can help!
>>
[quoted text clipped - 14 lines]
>
>Regards, Martin.
Should work fine but the combination of more than
doubled power from the motor with torque doubled again by the new
gearbox ratio may give you spectacular initial acceleration.
Let us know how you get on.
Jim