On Oct 8, 3:16 pm, "Graham Harrison"
<edward.harris...@remove.btinternet.com> wrote:
> > In message
> > <c3315fb0-f7ed-45f2-8799-813e04584...@s20g2000prd.googlegroups.com>,
[quoted text clipped - 19 lines]
>
> *If* it's DCC it needs 16(?)v AC doesn't it?
No. Some system may be able to run from low voltage AC from a
transformer but they will all run from an equivalent[1] DC source.
MBQ
[1] Taking account of RMS/peak voltage and allowing for the drop in
the rectifier diodes.
google@sheerstock.fsnet.co.uk - 08 Oct 2008 19:24 GMT
On Oct 8, 3:29 pm, "manatba...@hotmail.com" <manatba...@hotmail.com>
wrote:
> On Oct 8, 3:16 pm, "Graham Harrison"
>
[quoted text clipped - 34 lines]
> [1] Taking account of RMS/peak voltage and allowing for the drop in
> the rectifier diodes.
Should have also added that if running a system, designed to take AC,
from DC you may need to derate the booster ratings. All of the input
current will be flowing through only half of the rectifier, instead of
using both halves on opposite half cycles, so the power dissipation
will be doubled in two of the diodes. They may be spec'ed by the
maufacturer to allow for this, or not.
MBQ
>*If* it's DCC it needs 16(?)v AC doesn't it?
>
>I'm guessing that there is no commercially available controller than
>can accept 12vDC from the battery even though the output (for a DC
>layout) would be 12vDC as well. Mind you, I'm assuming HO - those
>pictures look more O like.
The blurb on the original says that it is G scale so it probably needs
something greater than 12v to operate.
>The inverter is changing 12vDC to 110vAC which is the US standard so
>they can use a standard controller at a guess.

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